Matrices and Determinants 4 Question 18
19. Given, $2 x-y+2 z=2, x-2 y+z=-4, \quad x+y+\lambda z=4$, then the value of $\lambda$ such that the given system of equations has no solution, is
(2004, 1M)
(a) 3
(b) 1
(c) 0
(d) -3
Show Answer
Answer:
Correct Answer: 19. (b)
Solution:
- Since, given system has no solution.
$\therefore \Delta=0$ and any one amongst $\Delta _x, \Delta _y, \Delta _z$ is non-zero.
[
]
