Indefinite Integration 3 Question 22

22. Investigate for maxima and minima the function,

f(x)=1x[2(t1)(t2)3+3(t1)2(t2)2]dt.

(1988,5 M)

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Solution:

  1. Given, f(x)=1x[2(t1)(t2)3+3(t1)2(t2)2]dt

f(x)=[2(x1)(x2)3+3(x1)2(x2)2]10

=(x1)(x2)2[2(x2)+3(x1)]

=(x1)(x2)2(5x7)

f(x) attains maximum at x=1 and f(x) attains minimum at x=75.



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