Circle 5 Question 6

6. The locus of the mid-point of a chord of the circle x2+y2=4 which subtends a right angle at the origin, is

(a) x+y=2

(b) x2+y2=1

(1984, 2M)

(c) x2+y2=2

(d) x+y=1

Objective Question II

(One or more than one correct option)

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Answer:

Correct Answer: 6. (c)

Solution:

  1. We have to find locus of mid-point of chord and we know perpendicular from centre bisects the chord.

OAC=45

In OAC,

OCOA=sin45

OC=22=2

Also,

h2+k2=OC2

Hence, x2+y2=2 is required equation of locus of mid-point of chord subtending right angle at the centre.



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