Binomial Theorem 1 Question 19

21. Coefficient of t24 in (1+t2)12(1+t12)(1+t24) is

(a) 12C6+3

(b) 12C6+1

(c) 12C6

(d) 12C6+2

(2003, 1M)

Show Answer

Solution:

  1. Here, Coefficient of t24 in (1+t2)12(1+t12)(1+t24) = Coefficient of t24 in (1+t2)12(1+t12+t24+t36) = Coefficient of t24 in

(1+t2)12+t12(1+t2)12+t24(1+t2)12

[neglecting t36(1+t2)12 ]

= Coefficient of t24=(12C12+12C6+12C0)=2+12C6



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