Application of Derivatives 4 Question 33

35. If f(x) is a cubic polynomial which has local maximum at x=1. If f(2)=18,f(1)=1 and f(x) has local minimum at x=0, then

(2006, 3M)

(a) the distance between (1,2) and (a,f(a)), where x=a is the point of local minima, is 25

(b) f(x) is increasing for x[1,25]

(c) f(x) has local minima at x=1

(d) the value of f(0)=5

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Answer:

Correct Answer: 35. (a)

Solution:

  1. Since, f(x) has local maxima at x=1 and f(x) has local minima at x=0.

f(x)=λx

On integrating, we get

f(x)=λx22+c[f(1)=0]λ2+c=0λ=2c

Again, integrating on both sides, we get

f(x)=λx36+cx+d

f(2)=λ86+2c+d=18 and f(1)=λ6+c+d=1

From Eqs. (i), (ii) and (iii),

f(x)=14(19x357x+34)f(x)=14(57x257)=574(x1)(x+1)

For maxima or minima, put f(x)=0x=1,1

Now

f(x)=14(114x)

 At x=1,f(x)>0, minima  At x=1,f(x)<0, maxima 

f(x) is increasing for [1,25].

f(x) has local maxima at x=1 and f(x) has local minima at x=1.

Also, f(0)=34/4

Hence, (b) and (c) are the correct answers.



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