SATHEE: 3D Geometry 3 Question 49

3D Geometry 3 Question 49

49. The value of $k$ such that $\frac{x - 4}{1} = \frac{y - 2}{1} = \frac{z - k}{2}$ lies in the plane $2 x - 4 y + z = 7$ , is

(2003, 1M)

(a) 7

(b) -7

(d) 4

Objective Question II

(One or more than one correct option)

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Answer:

Correct Answer: 49. (a)

Solution:

Given equation of straight line

$\frac{x - 4}{1} = \frac{y - 2}{1} = \frac{z - k}{2}$

Since, the line lies in the plane $2 x - 4 y + z = 7$ .

Hence, point $(4, 2, k)$ must satisfy the plane.

$\Rightarrow 8 - 8 + k = 7 \Rightarrow k = 7$

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3D Geometry 3 Question 49

49. The value of k such that x−41=y−21=z−k2 lies in the plane 2x−4y+z=7, is

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Answer:

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49. The value of $k$ such that $\frac{x - 4}{1} = \frac{y - 2}{1} = \frac{z - k}{2}$ lies in the plane $2 x - 4 y + z = 7$ , is