SATHEE: 3D Geometry 3 Question 32

3D Geometry 3 Question 32

32. If the image of the point $P (1, - 2, 3)$ in the plane $2 x + 3 y - 4 z + 22 = 0$ measured parallel to the line $\frac{x}{1} = \frac{y}{4} = \frac{z}{5}$ is $Q$ , then $P Q$ is equal to

(a) $3 \sqrt{5}$

(b) $2 \sqrt{42}$

(d) $6 \sqrt{5}$

(2017 Main)

Show Answer

Answer:

Correct Answer: 32. (a)

Solution:

Any line parallel to $\frac{x}{1} = \frac{y}{4} = \frac{z}{5}$ and passing through $P (1, - 2, 3)$ is

$\frac{x - 1}{1} = \frac{y + 2}{4} = \frac{z - 3}{5} = λ$

Any point on above line can be written as

$(λ + 1, 4 λ - 2, 5 λ + 3)$

$∴$ Coordinates of $R$ are $(λ + 1, 4 λ - 2, 5 λ + 3)$ .

Since, point $R$ lies on the above plane.

$∴ 2 (λ + 1) + 3 (4 λ - 2) - 4 (5 λ + 3) + 22 = 0$

$\Rightarrow λ = 1$

So, point $R$ is $(2, 2, 8)$ .

Now, $P R = \sqrt{(2 - 1)^{2} + (2 + 2)^{2} + (8 - 3)^{2}} = \sqrt{42}$

$∴ P Q = 2 P R = 2 \sqrt{42}$

पिछला

अगला

गोपनीयता नीति

द्वारा संचालित Prutor@IITK

sathee@iitk.ac.in

SATHEE का मीडिया कवरेज

खेल स्टोर

ऐप स्टोर

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

3D Geometry 3 Question 32

32. If the image of the point P(1,−2,3) in the plane 2x+3y−4z+22=0 measured parallel to the line x1=y4=z5 is Q, then PQ is equal to

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu

32. If the image of the point $P (1, - 2, 3)$ in the plane $2 x + 3 y - 4 z + 22 = 0$ measured parallel to the line $\frac{x}{1} = \frac{y}{4} = \frac{z}{5}$ is $Q$ , then $P Q$ is equal to