3D Geometry 3 Question 14

14. The equation of a plane containing the line of intersection of the planes 2xy4=0 and y+2z4=0 and passing through the point (1,1,0) is

(2019 Main, 8 April I)

(a) x3y2z=2

(b) 2xz=2

(c) xyz=0

(d) x+3y+z=4

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Answer:

(c)

Solution:

  1. Equations of given planes are

 and 2xy4=0y+2z4=0

Now, equation of family of planes passes through the line of intersection of given planes (i) and (ii) is

(2xy4)+λ(y+2z4)=0

According to the question,

Plane (iii) passes through the point (1,1,0), so

(214)+λ(1+04)=033λ=0λ=1

Now, equation of required plane can be obtained by putting λ=1 in the equation of plane (iii).

(2xy4)1(y+2z4)=02xy4y2z+4=02x2y2z=0xyz=0



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