SATHEE: Transition and InnerTransition Elements

Transition and InnerTransition Elements - Result Question 162

####62. Consider the following list of reagents, acidified $K_{2} C r_{2} O_{7}$ , alkaline $K M n O_{4}, C u S O_{4}, H_{2} O_{2}, C l_{2}, O_{3}, F e C l_{3}, H N O_{3}$ and $N a_{2} S_{2} O_{3}$ . The total number of reagents that can oxidise aqueous iodide to iodine is

(2014 Adv.)

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Answer:

Correct Answer: 62. (7)

Solution:

Acidified $K_{2} C r_{2} O_{7}, C u S O_{4}, H_{2} O_{2}, C l_{2}, O_{3}, F e C l_{3}$ and $H N O_{3}$ oxidise aq. iodide to iodine. Alkaline $K M n O_{4}$ oxidise aq. iodide to $I O_{3}^{-}$ . $N a_{2} S_{2} O_{3}$ is a strong reducing agent which on reaction with $I_{2}$ produces $I^{-}$ .

$N a_{2} S_{2} O_{3} + I_{2} ⟶ 2 I^{-} + N a_{2} S_{4} O_{6}$

Therefore, no reaction takes place between $N a_{2} S_{2} O_{3}$ and iodide ion.

Hence, correct integer is (7).

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Transition and InnerTransition Elements - Result Question 162

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