SATHEE: Transition and InnerTransition Elements

Transition and InnerTransition Elements - Result Question 10

####11. The $71^{st}$ electron of an element $X$ with an atomic number of 71 enters into the orbital

(2019 Main, 10 Jan II)

(a) $4 f$

(b) $6 p$

(d) $6 s$

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Solution:

In the lanthanoid series, atomic number of fourteen $4 f$ -block elements ranges from $58 (C e)$ to $71 (L u)$ .

Ytterbium, $Y b (Z = 70)$ has electronic configuration : $[X e] 4 f^{14} 6 s^{2}$ . So, the 71 nth electron of lutetium, $L u (Z = 71)$ should enter into $5 d$ orbital and its (here, $L u$ is ’ $X$ ‘) electronic configuration will be : $[X e] 4 f^{14} 5 d^{1} 6 s^{2}$ . It happens so, because $f$ -block elements have general electronic configuration, $(n - 2) f^{1 - 14} (n - 1) d^{1 - 10} n s^{2}$ . Therefore, option (c) is correct.

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Transition and InnerTransition Elements - Result Question 10

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