Thermodynamics and Thermochemistry - Result Question 38
####38. The difference between heats of reaction at constant pressure and constant volume for the reaction
$$ 2 C _6 H _6(l)+15 O _2 \longrightarrow 12 CO _2(g)+6 H _2 O(l) $$
at $25^{\circ} C$ in $kJ$ is
(a) -7.43
(b) +3.72
(c) -3.72
(d) +7.43
$(1991,1 M)$
Objective Questions II
(One or more than one correct option)
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Solution:
- $\Delta H=\Delta E+\Delta n _g R T \Rightarrow \Delta H-\Delta E=\Delta n _g R T=-3 R T$
$$ =-3 \times 8.314 \times 298=-7433 J=-7.43 kJ $$
