States of Matter - Result Question 96
####96. Calculate the density of $NH _3$ at $30^{\circ} C$ and $5 atm$ pressure.
$(1978,2 M)$
(d) $CH _3 OH$ $KCl$ $CH _3\left(CH _2\right) _{11} OSO _3^{-} Na^{+}$
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Solution:
- The ideal gas equation :
$$ \begin{aligned} p V & =n R T=\frac{w}{M} R T \ \Rightarrow \quad p M & =\frac{w}{V} R T=d R T \text { where, ’ } d \text { ’ is density. } \ \Rightarrow \quad d & =\frac{p M}{R T}=\frac{5 \times 17}{0.082 \times 303}=3.42 g L^{-1} . \end{aligned} $$
