Some Basic Concepts of Chemistry - Result Question 79
####17. The oxidation number of sulphur in $S _8, S _2 F _2, H _2 S$ respectively, are
(1999)
(a) $0,+1$ and -2
(b) $+2,+1$ and -2
(c) $0,+1$ and +2
(d) $-2,+1$ and -2
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Solution:
- $\frac{n _{O _2}}{n _{N _2}}=\frac{\frac{\left(m _{O _2}\right)}{\left(M _{O _2}\right)}}{\frac{\left(m _{N _2}\right)}{\left(M _{N _2}\right)}}$
$=0.9 \times 60 mg=54 mg$
where, $m _{O _2}$ = given mass of $O _2, m _{N _2}=$ given mass of $N _2$, $M _{O _2}=$ molecular mass of $O _2, M _{N _2}=$ molecular mass of $N _2$, $n _{O _2}=$ number of moles of $O _2, n _{N _2}=$ number of moles of $N _2$
$$ =\left[\frac{m _{O _2}}{m _{N _2}}\right] \frac{28}{32}=\frac{1}{4} \times \frac{28}{32}=\frac{7}{32} $$
