SATHEE: Some Basic Concepts of Chemistry

Some Basic Concepts of Chemistry - Result Question 53

####52. $n$ -butane is produced by monobromination of ethane followed by Wurtz’s reaction.Calculate volume of ethane at NTP required to produce $55 g n$ -butane, if the bromination takes place with $90$ yield and the Wurtz’s reaction with $85$ yield.

(1989, 3M)

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Solution:

Reactions involved are

$\begin{aligned} C_{2} H_{6} + B r_{2} & ⟶ C_{2} H_{5} B r + H B r 2 C_{2} H_{5} B r + 2 N a & ⟶ C_{4} H_{10} + 2 N a B r \end{aligned}$

Actual yield of $C_{4} H_{10} = 55 g$ which is $85$ of theoretical yield.

$\Rightarrow$ Theoretical yield of $C_{4} H_{10} = \frac{55 \times 100}{85} = 64.70 g$

Also, 2 moles ( $218 g$ ) $C_{2} H_{5} B r$ gives $58 g$ of butane.

$\Rightarrow 64.70 g$ of butane would be obtained from

$\frac{2}{58} \times 64.70 = 2.23 moles C_{2} H_{5} B r$

Also yield of bromination reaction is only $90$ , in order to have 2.23 moles of $C_{2} H_{5} B r$ , theoretically

$\frac{2.23 \times 100}{90} = 2.48 moles of C_{2} H_{5} B r required.$

Therefore, moles of $C_{2} H_{6}$ required $= 2.48$

$\Rightarrow$ Volume of $C_{2} H_{6}$ (NTP) required $= 2.48 \times 22.4 = 55.55 L$ .

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Some Basic Concepts of Chemistry - Result Question 53

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Some Basic Concepts of Chemistry - Result Question 53

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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