Some Basic Concepts of Chemistry - Result Question 38
####38. The total number of electrons present in $18 mL$ of water is
(1980, 1M)
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Solution:
- Considering density of water to be $1.0 g / mL, 18 mL$ of water is $18 g(1.0 mol)$ of water and it contain Avogadro number of molecules. Also one molecule of water contain
$2 \times($ one from each $H$-atom $)+8 \times($ from oxygen atom $)$
$$ =10 \text { electrons. } $$
$\Rightarrow 1.0$ mole of $H _2 O$ contain $=10 \times 6.023 \times 10^{23}$
$$ =6.023 \times 10^{24} \text { electrons. } $$
