Some Basic Concepts of Chemistry - Result Question 37
####37. $3.0 g$ of a salt of molecular weight 30 is dissolved in $250 g$ water. The molarity of the solution is
(1983, 1M)
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Solution:
- Molarity $=\frac{\text { Number of moles of solute }}{\text { Volume of solution in litre }}$
$$ \begin{aligned} & =\frac{\text { Weight of solute }}{\text { Molar mass }} \times \frac{1000}{\text { Volume in } mL} \ & =\frac{3}{30} \times \frac{1000}{250}=0.4 M \end{aligned} $$
