Some Basic Concepts of Chemistry - Result Question 37

####37. $3.0 g$ of a salt of molecular weight 30 is dissolved in $250 g$ water. The molarity of the solution is

(1983, 1M)

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Solution:

  1. Molarity $=\frac{\text { Number of moles of solute }}{\text { Volume of solution in litre }}$

$$ \begin{aligned} & =\frac{\text { Weight of solute }}{\text { Molar mass }} \times \frac{1000}{\text { Volume in } mL} \ & =\frac{3}{30} \times \frac{1000}{250}=0.4 M \end{aligned} $$



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