Some Basic Concepts of Chemistry - Result Question 107
####45. Find the molarity of water. Given: $\rho=1000 kg / m^{3}$
(2003)
Show Answer
Solution:
- Mass of $1.0 L$ water $=1000 g$
$\Rightarrow \quad$ Molarity $=\frac{1000}{18}=55.56 mol L^{-1}$
####45. Find the molarity of water. Given: $\rho=1000 kg / m^{3}$
(2003)
$\Rightarrow \quad$ Molarity $=\frac{1000}{18}=55.56 mol L^{-1}$
Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓
I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".
