Some Basic Concepts of Chemistry - Result Question 100

####38. The total number of electrons present in $18 mL$ of water is

(1980, 1M)

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Solution:

  1. Considering density of water to be $1.0 g / mL, 18 mL$ of water is $18 g(1.0 mol)$ of water and it contain Avogadro number of molecules. Also one molecule of water contain

$2 \times($ one from each $H$-atom $)+8 \times($ from oxygen atom $)$

$$ =10 \text { electrons. } $$

$\Rightarrow 1.0$ mole of $H _2 O$ contain $=10 \times 6.023 \times 10^{23}$

$$ =6.023 \times 10^{24} \text { electrons. } $$



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