Solutions and Colligative Properties - Result Question 64
####35. The freezing point of the solution $M$ is
(a) $268.7 K$
(b) $268.5 K$
(c) $234.2 K$
(d) $150.9 K$
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Solution:
- In the given solution ’ $M$ ‘, $H _2 O$ is solute.
Therefore, molality of $H _2 O=\frac{0.1}{0.9 \times 46} \times 1000=2.4$
$$ \begin{array}{rlrl} \Rightarrow & -\Delta T _f & =K _f^{\text {ethanol }} \times 2.4=2 \times 2.4=4.8 \ \Rightarrow & & T _f & =155.7-4.8=150.9 K \end{array} $$
