SATHEE: Solutions and Colligative Properties

Solutions and Colligative Properties - Result Question 53

####24. The vapour pressure of ethanol and methanol are 44.5 and $88.7 m m H g$ respectively. An ideal solution is formed at the

Topic 2 Colligative Properties

Objective Questions I (Only one correct option)

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Solution:

Moles of ethanol $= \frac{60}{46} = 1.3$

Moles of methanol $= \frac{40}{32} = 1.25$

$\Rightarrow$ Mole fraction of ethanol $= \frac{1.3}{1.3 + 1.25} = 0.51$

$\Rightarrow$ Vapour pressure of solution $= p_{ethanol} + p_{methanol}$ $= 0.51 \times 44.5 + 0.49 \times 88.7$

$= 66.16 m m$

Mole fraction of methanol in vapour phase

$\begin{aligned} = \frac{p_{methanol}}{Total vapour pressure} & = \frac{43.463}{66.16} = 0.657 \end{aligned}$

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Solutions and Colligative Properties - Result Question 53

Topic 2 Colligative Properties

Objective Questions I (Only one correct option)

Solution:

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