SATHEE: Solid State - Result Question 26

Solid State - Result Question 26

####26. If the unit cell of a mineral has cubic close packed (ccp) array of oxygen atoms with $m$ fraction of octahedral holes occupied by aluminium ions and $n$ fraction of tetrahedral holes occupied by magnesium ions, $m$ and $n$ respectively, are

(a) $\frac{1}{2}, \frac{1}{8}$

(b) $1, \frac{1}{4}$

(d) $\frac{1}{4}, \frac{1}{8}$

(2015 Adv.)

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Answer:

Correct Answer: 26. (a)

Solution:

Oxide ions are at ccp positions, hence $4 O^{2 -}$ ions. Also, there are four octahedral voids and eight tetrahedral voids. Since ’ $m$ ’ fraction of octahedral voids contain $A l^{3 +}$ and ’ $n$ ’ fraction of tetrahedral voids contain $M g^{2 +}$ ions, to maintain etectroneutrality $2 (2 A l^{3 +} = + 6$ charge $)$ and $(M g^{2 +} = + 2$ charge $)$ , will make unit cell neutral

Hence: $m = \frac{2}{4} = \frac{1}{2}, n = \frac{1}{8}$

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Solid State - Result Question 26

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