sblock Elements - Result Question 67
####20. $MgCl _2 \cdot 6 H _2 O$ on heating gives anhydrous $MgCl _2$.
$(1982,1 M)$
Subjective Questions
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Answer:
Correct Answer: 20. $F$
Solution:
- $\mathbf{M g}$ can form basic carbonate while $\mathbf{~} \mathbf{i}$ cannot.
$5 Mg^{2+}+6 CO _3^{2-}+7 H _2 O \longrightarrow 4 MgCO _3 \cdot Mg(OH) _2$
$$ \cdot 5 H _2 O+2 HCO _3^{-} $$
