sblock Elements - Result Question 26

####25. Arrange the following in increasing order of basic strength :

MgO,SrO,K2O,NiO,Cs2O

(1991, 1M)

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Solution:

  1. PLAN This problem can be solved by using concept of oxidant and reductant.

Oxidant Oxidant increases the oxidation number of the species with which it is reacted.

Reductant Reductant decreases the oxidation number of the species with which it is reacted.

H2O2 reacts with KIO4 in the following manner:

On reaction of KIO4 with H2O2, oxidation state of I varies from +7 to +5 , i.e. decreases. Thus, KIO4 gets reduced hence, H2O2 is a reducing agent here.

With NH2OH, it given following reaction:

N1H2OH+H2O2N2+3O3+H2O

In the above reaction, oxidation state of N varies from -1 to +3 . Here, oxidation number increases, hence H2O2 is acting as an oxidising agent here.

Hence, (a) is the correct choice.



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