####70. The gas liberated, on heating a mixture of two salts with , gives a reddish brown precipitate with an alkaline solution of . The aqueous solution of the mixture on treatment with gives a white precipitate which is sparingly soluble in conc. .
On heating the mixture with and conc. , red vapours are produced. The aqueous solution of the mixture gives a deep blue colouration with potassium ferricyanide solution. Identify the radicals in the given mixture and write the balanced equations for the formation of and .
Show Answer
Solution:
- Formation of a reddish-brown precipitate with alkaline solution indicates the presence of ion and the gas liberated is ammonia :
On treatment with , a white precipitate is formed which indicates the presence of anion :
With and conc. , red vapour of is evolved. This indicates presence of ion.
On treatment with potassium ferricyanide, formation of deep blue solution indicates presence of (II) ion :
