Qualitative Analysis - Result Question 55

####58. An aqueous solution containing one mole of HgI2 and two moles of NaI is orange in colour. On addition of excess NaI the solution becomes colourless. The orange colour reappears on subsequent addition of NaOCl. Explain with equations.

(1999, 3M)

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Solution:

  1. NaI on reaction with HgI2 gives a complex salt :

2NaI+HgI2Na2[HgI4]

The orange colour is due to residual HgI2. On addition of excess NaI, whole HgI2 is converted to complex Na2[HgI4] as colour disappear. The orange colour of HgI2 reappear due to conversion of Na2[HgI4] into HgI2 on treatment with NaOCl.

3Na2[HgI4]+2NaOCl+2H2O3HgI2+2NaCl +4NaOH+2NaI



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