Qualitative Analysis - Result Question 24

####24. The correct option(s) to distinguish nitrate salts to Mn2+ and Cu2+ taken separately is (are)

(2018 Adv.) (a) Mn2+ shows the characteristic green colour in the flame test

(b) Only Cu2+ shows the formation of precipitate by passing H2S in acidic medium

(c) Only Mn2+ shows the formation of precipitate by passing H2S in faintly basic medium

(d) Cu2+/Cu has higher reduction potential than Mn2+/Mn (measured under similar conditions)

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Solution:

  1. Statement wise explanation is

Statement (a) Mn2+ produces yellow-green colour in flame test while Cu2+ produces bluish-green colour in flame test. Thus, due to the presence of green colour in both the cases, flame test is not the suitable method to distinguish between nitrate salts of Cu2+ and Mn2+. Hence this statement is wrong.

Statement (b) Cu2+ belong to group II of cationic or basic radicals. It gives black ppt. of CuS if H2S is passed through it in the presence of acid (e.g HCl). Mn2+ does not show this property hence this can be considered as a suitable method to distinguish between Mn2+ and Cu2+.

Hence, this statement is correct.

Statement (c) In faintly basic medium when H2S is passed both Cu2+ and Mn2+ forms precipitates. Thus, it is not suitable method to distinguish between them.

Hence, this statement is incorrect

Statement (d) The standard reduction potential of Cu2+/Cu is +0.34V while that of Mn2+/Mn is 1.18V. This can be used to distinguish between Cu2+ and Mn2+. In general less electropositive metals have higher SRP.

Hence, this statement is correct.



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