Qualitative Analysis - Result Question 2

####2. When metal ’ M ’ is treated with NaOH, a white gelatinous precipitate ’ X ’ is obtained, which is soluble in excess of NaOH. Compound ’ X ’ when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal ’ M ’ is

(2018 Main)

(a) Zn

(b) Ca

(c) Al

(d) Fe

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Solution:

  1. Among the given metals Al forms white gelatinous ppt. with NaOH.

Hence, the probable metal can be Al. This ppt. is dissolved in excess of NaOH due to the formation of sodium metal Aluminate. Both the reactions are shown below.

Aluminium hydroxide on strong heating gives alumina (Al2O3) which is used as an adsorbent in chromatography. This reaction can be seen as :

2Al(OH)3ΔAl2O3+3H2O

Thus, metal M is Al.

Ca, being below sodium in electrochemical reactivity series, cannot displaces Na from its aqueous solution.

Zn reacts with NaOH to form sodium zincate which is a soluble compound.

Fe reacts with sodium hydroxide to form tetrahydroferrate (II) sodium which is again a soluble complex.



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