Periodic Classification and Periodic Properties - Result Question 19

####16. Which of the following has the maximum number of unpaired electrons?

(a) $Mg^{2+}$

(b) $Ti^{3+}$

(c) $V^{3+}$

(d) $Fe^{2+}$

$(1996,1 M)$

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Answer:

Correct Answer: 16. (b)

Solution:

  1. $Mg^{2+}=1 s^{2} 2 s^{2} 2 p^{6}=$ no unpaired electron

$Ti^{3+}=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{1}=$ one unpaired electron

$V^{3+}=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{2}=$ two unpaired electrons

$Fe^{2+}=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{6}=$ four unpaired electrons



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