Periodic Classification and Periodic Properties - Result Question 19
####16. Which of the following has the maximum number of unpaired electrons?
(a) $Mg^{2+}$
(b) $Ti^{3+}$
(c) $V^{3+}$
(d) $Fe^{2+}$
$(1996,1 M)$
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Answer:
Correct Answer: 16. (b)
Solution:
- $Mg^{2+}=1 s^{2} 2 s^{2} 2 p^{6}=$ no unpaired electron
$Ti^{3+}=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{1}=$ one unpaired electron
$V^{3+}=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{2}=$ two unpaired electrons
$Fe^{2+}=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{6}=$ four unpaired electrons
