Periodic Classification and Periodic Properties - Result Question 13

####10. The first ionisation potential of $Na$ is $5.1 eV$. The value of electron gain enthalpy of $Na^{+}$will be

(a) $-2.55 eV$

(b) $-5.1 eV$

(c) $-10.2 eV$

(d) $+2.55 eV$

(2013 Main)

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Answer:

Correct Answer: 10. (b)

Solution:

$$ \begin{aligned} Na & \longrightarrow Na^{+}+e^{-} \text {First IE } \ Na^{+}+e^{-} & \longrightarrow Na \end{aligned} $$

Electron gain enthalpy of $Na^{+}$is reverse of (IE)

Because reaction is reverse so $\Delta H(e q)=-5.1 eV$



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