pBlock ElementsII - Result Question 160
####48. Ammonia, on reaction with hypochlorite anion, can form
(a) $NO$
(b) $NH _4 Cl$
(c) $N _2 H _4$
(d) $HNO _2$
(1999, 3M)
Show Answer
Solution:
- $2 NH _3+OCl^{-} \longrightarrow H _2 N-NH _2+H _2 O+Cl^{-}$
####48. Ammonia, on reaction with hypochlorite anion, can form
(a) $NO$
(b) $NH _4 Cl$
(c) $N _2 H _4$
(d) $HNO _2$
(1999, 3M)
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