pBlock ElementsII - Result Question 124
####9. The order of the oxidation state of the phosphorus atom in $H _3 PO _2, H _3 PO _4, H _3 PO _3$ and $H _4 P _2 O _6$ is
(2017 Adv.)
(a) $H _3 PO _4>H _3 PO _2>H _3 PO _3>H _4 P _2 O _6$
(b) $H _3 PO _4>H _4 P _2 O _6>H _3 PO _3>H _3 PO _2$
(c) $H _3 PO _2>H _3 PO _3>H _4 P _2 O _6>H _3 PO _4$
(d) $H _3 PO _3>H _3 PO _2>H _3 PO _4>H _4 P _2 O _6$
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Solution:
- $H _3 \stackrel{+5}{P} O _4>H _4 \stackrel{+4}{P _2} O _6>H _3 \stackrel{+3}{P} O _3>H _3 \stackrel{+1}{P} O _2$
