p-Block Elements-I - Result Question 52
####23. Three moles of $B _2 H _6$ are completely reacted with methanol. The number of moles of boron containing product formed is
(2015 Adv.)
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Solution:
- $B _2 H _6+6 CH _3 OH \longrightarrow 2\left[B\left(OCH _3\right) _3\right]+6 H _2$
Therefore, from 3 moles of $B _2 H _6, 6$ moles of $B\left(OCH _3\right) _3$ will be
