SATHEE: p-Block Elements-I - Result Question 15

p-Block Elements-I - Result Question 15

####15. In the reaction, $2 X + B_{2} H_{6} ⟶ {[B H_{2} (X)_{2}]}^{+} {[B H_{4}]}^{-}$ the amine(s) $X$ is/are

(2009)

(a) $N H_{3}$

(b) $C H_{3} N H_{2}$

(d) ${(C H_{3})}_{3} N$

Assertion and Reason

Read the following questions and answer as per the direction given below:

(a) Statement I is correct; Statement II is correct Statement II is the correct explanation of Statement I

(b) Statement I is correct; Statement II is correct Statement II is not the correct explanation of Statement I

(d) Statement I is incorrect; Statement II is correct

Show Answer

Answer:

Correct Answer: 15. (a)

Solution:

Diborane $(B_{2} H_{6})$ undergoes unsymmetric cleavage with $N H_{3}$ , primary and secondary amine while tertiary amine brings about symmetrical cleavage of $B_{2} H_{6}$ as :

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p-Block Elements-I - Result Question 15

Assertion and Reason

Answer:

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