####56. The compound in which $C$ uses its $s p^{3}$-hybrid orbitals for bond formation is
(a) $HCOOH$
(b) $\left(H _2 N\right) _2 CO$
(c) $\left(CH _3\right) _3 COH$
(d) $CH _3 CHO$
$(2000,1 M)$
56.
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