####17. The maximum number of isomers (including stereoisomers) that are possible on mono-chlorination of the following compound, is $CH _3 CH _2 CH\left(CH _3\right) CH _2 CH _2$
(2011)
Correct Answer: 17. (c)
Solution:
17.
I has one chiral carbon $=$ two isomers
II has two chiral carbons and no symmetry = four isomers.
III and IV have no chiral carbon, no stereoisomers.
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