Extraction of Metals - Result Question 15

####15. Hall-Heroult’s process is given by

(2019 Main, 10 Jan I)

(a) ZnO+C Coke, 1673KZn+CO

(b) Cr2O3+2AlAl2O3+2Cr

(c) 2Al2O3+3C4Al+3CO2

(d) Cu2+(aq)+H2(g)Cu(s)+2H+(aq)

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Solution:

  1. Hall-Heroult’s process is an electro-reduction process by which pure alumina (Al2O3) is reduced to crude Al.

In this process, electrolysis of a fused mixture of Al2O3, Na3[AlF6] (cryolite) and CaF2 (fluorspar) is carried out at carbon cathode and graphite anode.

The overall reaction is represented as:

2Al2O3+3C4Al+3CO2



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