Electrochemistry - Result Question 89
####37. The standard reduction-potential for the half-cell
$NO _3^{-}(a q)+2 H^{+}+e^{-} \longrightarrow NO _2(g)+H _2 O$ is $0.78 V$
(i) Calculate the reduction-potential in $8 M H^{+}$.
(ii) What will be the reduction-potential of the half-cell in a neutral solution? Assume all the other species to be at unit concentration.
(1993, 2M)
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Solution:
- (i) $E=0.78-0.0592 \log \frac{1}{8^{2}}=0.887 V$
(ii) $E=0.78-0.0592 \log \frac{1}{\left(10^{-7}\right)^{2}}=-0.0488 V$
