Electrochemistry - Result Question 82
####30. If the cathode is a $Hg$ electrode, the maximum weight (in gram) of amalgam formed from this solution is
(a) 200
(b) 225
(c) 400
(d) 446
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Solution:
- At cathode $Na^{+}+e^{-} \xrightarrow{Hg} \underset{\text { Amalgam }}{Na(Hg)}$
Two moles of $Na$ formed during electrolysis would produce two moles of $Na(Hg)$ amalgam.
$\Rightarrow$ mass of amalgam $=2 \times(23+200)=446 g$
