Electrochemistry - Result Question 31

####30. If the cathode is a $Hg$ electrode, the maximum weight (in gram) of amalgam formed from this solution is

(a) 200

(b) 225

(c) 400

(d) 446

Show Answer

Solution:

  1. At cathode $Na^{+}+e^{-} \xrightarrow{Hg} \underset{\text { Amalgam }}{Na(Hg)}$

Two moles of $Na$ formed during electrolysis would produce two moles of $Na(Hg)$ amalgam.

$\Rightarrow$ mass of amalgam $=2 \times(23+200)=446 g$



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