Electrochemistry - Result Question 11
####11. Given, $E _{Cr^{3+} / Cr}^{\circ}=-0.74 V ; E _{MnO _4^{-} / Mn^{2+}}^{\circ}=1.51 V$
Based on the data given above strongest oxidising agent will be
(2013 Main)
(a) $Cl$
(b) $Cr^{3+}$
(c) $Mn^{2+}$
(d) $MnO _4^{-}$
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Answer:
Correct Answer: 11. (d)
Solution:
- Higher the standard reduction potential, better is oxidising agent. Among the given $E _{MnO _4^{-} / Mn^{2+}}^{\circ}$ is highest, hence $MnO _4^{-}$is the strongest oxidising agent.
