Coordination Compounds 2 Question 4

####4. The crystal field stabilisation energy (CFSE) of [Fe(H2O)6]Cl2 and K2[NiCl4], respectively, are

(2019 Main, 10 April II)

(a) 0.4Δo and 1.2Δt

(b) 0.4Δo and 0.8Δt

(c) 2.4Δo and 1.2Δt

(d) 0.6Δo and 0.8Δt

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Solution:

Key Idea Crystal field stabilisation energy (CFSE) for octahedral complexes =(0.4x+0.6y)Δo

where, x= number of electrons occupying t2g orbital.

y= number of electrons occupying eg orbital.

CFSE for tetrahedral complexes

=(0.6x+0.4y)Δt

where, x= number of electrons occupying e orbital.

y= number of electrons occupying t orbital.

In [Fe(H2O)6]Cl2,H2O is a weak field ligand, so it is a high spin (outer orbital) octahedral complex of Fe2+.

Misplaced \hline

CFSE=(0.4x+0.6y)Δo

=[0.4×4+0.6×2]Δo=0.4Δo

In K2[NiCl4],Clis a weak field ligand, so it is a high spin tetrahedral complex of Ni2+.

CFSE=(0.6×4+0.4×4)Δt=0.8Δt



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