Coordination Compounds 2 Question 39
####41. Spin only magnetic moment of the compound $Hg\left[Co(SCN) _4\right]$ is
(a) $\sqrt{3}$
(b) $\sqrt{15}$
(c) $\sqrt{24}$
(d) $\sqrt{8}$
$(2004,1 M)$
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Solution:
- In $Hg\left[Co(SCN) _4\right], Co^{2+}$ has $3 d^{7}$ configuration. $SCN^{-}$produces weak ligand field, no pairing of electrons in $d$-orbitals occurs against Hund’s rule, hence :
