Coordination Compounds 1 Question 6

####6. The total number of isomers for a square planar complex [M(F)(Cl)(SCN)(NO2)] is

(2019 Main, 10 Jan I)

(a) 12

(b) 16

(c) 4

(d) 8

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Answer:

Correct Answer: 6. (c)

Solution:

  1. A square planar complex of general formula, Mabcd gives three geometrical isomers only.

Let, a=F,b=Cl,c=SCN,d=NO2

SCNand NO2are ambidentate ligands and they also show linkage isomerism (structural). Considering both linkage and geometrical isomerism.

Total number of possible isomers given by the complex,

=3×(2+2)=12



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