Chemical Bonding - Result Question 63

####38. The hybridisation of sulphur in sulphur dioxide is $(1986,1 M)$

(a) $s p$

(b) $s p^{3}$

(c) $s p^{2}$

(d) $d s p^{2}$

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Solution:

  1. In $SO _2$, the Lewis-dot structure is

$$ O=\ddot{S}=O $$

Electron pairs at $S=2(\sigma$-bonds $)+1$ (lone-pair) $=3$ $s p^{2}$ hybridised.

NOTE

$\pi$-bonded electrons are not present in hybrid orbitals, therefore not counted in electron pairs. Rather $\pi$ bonds are formed by lateral overlapping of pure $p$-orbitals.



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