Chemical Bonding - Result Question 14

####14. Among the species given below, the total number of diamagnetic species is

$H$ atom, $NO _2$ monomer, $O _2^{-}$(superoxide), dimeric sulphur in vapour phase, $Mn _3 O _4,\left(NH _4\right) _2\left[FeCl _4\right],\left(NH _4\right) _2\left[NiCl _4\right]$, $K _2 MnO _4, K _2 CrO _4$

(2018 Adv.)

Assertion and Reason

Read the following questions and answer as per the direction given below:

(a) Statement I is true; Statement II is true; Statement II is the correct explanation of Statement I

(b) Statement I is true; Statement II is true; Statement II is not the correct explanation of Statement I

(c) Statement I is correct; Statement II is incorrect

(d) Statement I is incorrect; Statement II is correct

Show Answer

Answer:

Correct Answer: 14. (1)

Solution:

  1. Among the given species only $K _2 CrO _4$ is diamagnetic as central metal atom $Cr$ in it has $[Ar] 3 d^{0}$ electronic configuration i.e., all paired electrons. The structure and oxidation state of central metal atom of this compound are as follows

Structure $K^{+}\left[\begin{array}{cc}\stackrel{O}{O} \ \stackrel{Cr}{Cr} \ O^{\prime} & O^{-}\end{array}\right]$, Oxidation state $O^{6+}$

Rest all the compounds are paramagnetic. Reasons for their paramagnetism are given below

(i) H-atom have $1 s^{1}$ electronic configuration, i.e. 1 unpaired electron.

(ii) $NO _2$, i.e. $\stackrel{\odot}{O / P^{\searrow}} \searrow _O$ in itself is an odd electron species.

(iii) $O _2^{-}$(Superoxide) has one unpaired electron in $\pi *$ molecular orbital.

(iv) $S _2$ in vapour phase has $O _2$ like electronic configuration i.e., have 2 unpaired electrons in $\pi *$ molecular orbitals.

(v) $Mn _3 O _4$ has following structure

Thus, $Mn$ is showing +2 and +4 oxidation states. The outermost electronic configuration of elemental $Mn$ is $3 d^{5} 4 s^{2}$. Hence, in both the above oxidation states it has unpaired electrons as

(vi) $\left(NH _4\right) _2 FeCl _4$ has $Fe$ as central metal atom with +2 oxidation state. The electronic configuration of $Fe^{2+}$ in the complex is

(vii) $\left(NH _4\right) _2 NiCl _4$ has $Ni$ as central metal atom with +2 oxidation state. The electronic configuration of $Ni^{2+}$ in the complex is

(viii) In $K _2 MnO _4$ central metal atom $Mn$ has +6 oxidation state with following structure

Electronic configuration of $Mn^{6+}$ is



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक