Chemical Bonding - Result Question 102

####1. The isoelectronic set of ions is

(2019 Main, 10 April I)

(a) $F^{-}, Li^{+}, Na^{+}$and $Mg^{2+}$

(b) $N^{3-}, Li^{+}, Mg^{2+}$ and $O^{2-}$

(c) $Li^{+}, Na^{+}, O^{2-}$ and $F^{-}$

(d) $N^{3-}, O^{2-}, F^{-}$and $Na^{+}$

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Answer:

Correct Answer: 1. (d)

Solution:

  1. Key Idea Isoelectronic species contains same number of electrons.

The species with its atomic number and number of electrons are as follows :

Species (ions) At. no. $(\boldsymbol{Z})$ No. of electrons
$N^{3-}$ 7 $7+3=10$
$O^{2-}$ 8 $8+2=10$
$F^{-}$ 9 $9+1=10$
$Na^{+}$ 11 $11-1=10$
$Li^{+}$ 3 $3-1=2$
$Mg^{2+}$ 12 $12-2=10$

Thus, option (d) contains isoelectronic set of ions.



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