Chemical and Ionic Equilibrium - Result Question 91
####35. The $pH$ of $10^{-8} M$ solution of $HCl$ in water is
$(1981,1 M)$
(a) 8
(b) -8
(c) between 7 and 8
(d) between 6 and 7
Objective Questions II
(One or more than one correct option)
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Solution:
- $C _2 H _4+H _2 \rightleftharpoons C _2 H _6, \Delta H=-32.7 kcal$
The above reaction is exothermic, increasing temperature will favour backward reaction, will increase the amount of $C _2 H _4$. Decreasing pressure will favour reaction in direction containing more molecules (reactant side in the present case). Therefore, decreasing pressure will increase amount of $C _2 H _4$. Removing $H _2$, which is a reactant, will favour reaction in backward direction, more $C _2 H _4$ will be formed.
Adding $C _2 H _6$ will favour backward reaction and some of the $C _2 H _6$ will be dehydrogenated to $C _2 H _4$.
