Chemical and Ionic Equilibrium - Result Question 5

####5. In a chemical reaction, A+2BK2C+D, the initial concentration of B was 1.5 times of the concentration of A, but the equilibrium concentrations of A and B were found to be equal. The equilibrium constant (K) for the aforesaid chemical reaction is

(2019 Main, 12 Jan I)

(a) 14

(b) 16

(c) 1

(d) 4

Show Answer

Answer:

Correct Answer: 5. (a)

Solution:

  1. For the given chemical reaction,

A+2B2C+D  At t=025a  At, t=0a01.5a000 t=teqa0x1.5a02x2xx

[x= degree of dissociation ]

Given, at equilibrium.

[A]=[B] a0x=1.5a02x x=0.5a0 [A]=a0x=a00.5a0=0.5a0 [B]=1.5a02x=1.5a02×0.5a0=0.5a0 [C]=2x=2×0.5a0=a0 [D]=x=0.5a0

Now, K=[C]2[D][A][B]2

Now, substituting the values in above equation, we get

K=(a0)2×(0.5a0)(0.5a0)×(0.5a0)=4



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक