SATHEE: Chemical and Ionic Equilibrium

Chemical and Ionic Equilibrium - Result Question 35

####35. The $p H$ of $10^{- 8} M$ solution of $H C l$ in water is

$(1981, 1 M)$

(a) 8

(b) -8

(d) between 6 and 7

Objective Questions II

(One or more than one correct option)

Show Answer

Solution:

$C_{2} H_{4} + H_{2} ⇌ C_{2} H_{6}, Δ H = - 32.7 k c a l$

The above reaction is exothermic, increasing temperature will favour backward reaction, will increase the amount of $C_{2} H_{4}$ . Decreasing pressure will favour reaction in direction containing more molecules (reactant side in the present case). Therefore, decreasing pressure will increase amount of $C_{2} H_{4}$ . Removing $H_{2}$ , which is a reactant, will favour reaction in backward direction, more $C_{2} H_{4}$ will be formed.

Adding $C_{2} H_{6}$ will favour backward reaction and some of the $C_{2} H_{6}$ will be dehydrogenated to $C_{2} H_{4}$ .

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Chemical and Ionic Equilibrium - Result Question 35

Objective Questions II

Solution:

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