Chemical and Ionic Equilibrium - Result Question 131

####73. The solubility of Mg(OH)2 in pure water is 9.57×103g/L. Calculate its solubility (in g/L ) in 0.02MMg(NO3)2 solution.

(1986,5M)

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Solution:

  1. In pure water, solubility =9.5758×103M

=1.65×104M

Ksp =4S3=4(1.65×104)3=1.8×1011

In 0.02MMg(NO3)2; solubility of Mg(OH)2=Ksp [Mg2+]×12

=1.5×105molL1 =1.5×105×58gL1 =8.7×104gL1



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